Mixed Quantitative Aptitude Questions Set 164

Directions(1-10): Find the approximate value of the following questions.

1. 52.012% of 749.75 + 22.05 * ? = 874.07
   15
   10
   25
   22
   27
   Option D
   52.012% of 749.75 + 22.05 * ? = 874.07
   =>52% of 750 + 22*? = 874
   => 390 + 22*? = 874
   =>? = 22
   
   
    



2. 38.78^2 – 77.73*8.99 – 25.08*12.04 = ?
   400
   500
   200
   300
   100
   Option B
   38.78^2 – 77.73*8.99 – 25.08*12.04 = ?
   =>40^2 – 80*10 – 25*12 = ?
   =>1600 – 800 – 300 =?
   =>? = 500
   
   
    



3. 24.05*11.86 – 416.05/16.98 – 108.56 = ?
   140
   152
   120
   133
   148
   Option B
   24.05*11.86 – 416.05/16.98 – 108.56 = ?
   => 24*12 - 416/16 – 110 = ?
   =>288 – 26 – 110 = ?
   =>? = 152
   
   
    



4. 22.25% of 29.69% of 48.12% of 4260 = 50.08% of ?
   220
   245
   261
   258
   240
   Option D
   22.25% of 29.69% of 48.12% of 4260 = 50.08% of ?
   =>20% of 30% of 50% of 4300=50% of ?
   =>? = 258
   
   
    



5. (3100/124)*(8^3 /32) = ?^2
   10
   30
   40
   20
   50
   Option D
   (3100/124)*(8^3 /32) = ?^2
   =>?^2 = 25*(512/32)
   =>?^2 = 25*16
   =>? = 20
   
   
    



6. At what rate of interest an amount of Rs.16000 will become Rs.25000 in 2 years if the rate is compounded annually.
   27%
   22%
   25%
   15%
   20%
   Option C
   25000 = 16000{1+r/100}^2
   r = 25%
   
   
    



7. Five years ago, Rahul was 20 years elder than Raj. After 15 years, the ratio of their ages is 2:3. Find the average of their present ages.
   32 years
   25 years
   20 years
   30 years
   35 years
   Option E
   Let the present ages of Rahul and Raj be x and y resp.
   x = y +20 ----(1)
   And (y+15)/(x+15) = 2/3 ----(2)
   On solving both the equations, we get
   x = 45 years
   y = 25 years
   Average = 70/2 = 35 years
   
   
    



8. A shopkeeper marked his goods 60% above cost price and gave a discount of 25%. Find the profit percentage of shopkeeper.
   30%
   25%
   20%
   15%
   10%
   Option C
   Profit% = {(120-100)/100}*100 = 20%
   
    



9. A boat can cover 36 km upstream in 6 hours, and 84 km downstream in 7 hours. Find the ratio of speed of boat in still water to speed of stream.
   3:4
   2:5
   3:1
   4:1
   3:2
   Option C
   Required ratio =(12+6)/2 : (12-6)/2
   = 3:1
   
   
    



10. A 260 ml mixture contains water and acid in the ratio 6:7 resp. How much acid should be added to the mixture so that the ratio of water and acid changes to 3:5 resp.
    30 ml
    60 ml
    20 ml
    50 ml
    40 ml
    Option B
    Quantity of water = 120 ml
    Quantity of acid = 140 ml
    Now,
    120/(140+x) = 3/5
    => x= 60 ml