- ?^2 ={(75% of 24% of 1900)/19}+306
2014102218Option E
?^2 ={(75% of 24% of 1900)/19}+306
=>?^2 = 342/19 + 306
=>?^2 = 324
=>? = 18
- ?*12.5% of 64 = 12% of 25% of 200% of 5200
3039475240Option B
?*12.5% of 64 = 12% of 25% of 200% of 5200
=>?*8 = 312
=>? = 39
- ? / 0.5 = (1728)^1/3 * (784)^1/2 + (225)^1/2 *(1024)^1/2
444430415408420Option D
? / 0.5 = (1728)^1/3 * (784)^1/2 + (225)^1/2 *(1024)^1/2
=>?/0.5 = 28*12 + 15*32
=>?/0.5 =336 + 480
=>? = 408
- ?^2 = (15*14 ) / 7 + 24% of 1900 – 2
2230422838Option A
?^2 = (15*14 ) / 7 + 24% of 1900 – 2
=>?^2 = 30+456-2
=>? = 22
- ? = 20% of 5075 – 19^2 – 171
450440462472483Option E
? = 20% of 5075 – 19^2 – 171
=>1015 – 361 – 171 = ?
=>? = 483
- Ram, Shyam and Sita started a business in partnership by investing Rs.38500, Rs.49500 and X respectively. At the end of the year they earned a total profit of Rs.101500 and Riya’s share in the profit is 45500 find X ?
4422042781417204550042250Option D
X = 71500
38500*12:49500*12 : x*12 = 7:9:12x = 7:9:13
Profit = 101500*13/29 = 45500
- The area of a rectangle gets reduced by 9 square units,if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and breadth by 2 units, then the area is increased by 67 square units. Find the area of the rectangle?
163174153169175Option C
then the area is increased by 67 square units. Find the area of the rectangle?
Length = x; Breadth =y
xy – (x-5)(y+3) = 9
3x – 5y – 6 = 0 —(i)
(x+3)(y+2) – xy = 67
2x + 3y -61 = 0 —(ii)
solving (i) and (ii)
x = 17m ; y = 9m
Area of the Rectangle = 153 m
- The average salary of all the employees in company is 7000. The average salary of 9 mechanic is 5000 and for the rest of the employees it 4000. Find the total number of employees in the company.
2015101218Option D
Total Employees E,
7000*E = 9*5000 + (E-9)*4000.
E = 3
Hence, 3+9 =12
- A number is first decreased by 25%. The decreased number is then increased by 20%. The resulting number is less than the original number by 40. Find the original number.
345450400370330Option C
Let the number is x.
x – (75/100)*x*(120/100) = 40
x = 400
- A bag contains 2 red caps, 4 blue caps, 3 yellow caps and 5 green caps. If three caps are picked at random, what is the probability that none is green?
5/136/192/173/131/15Option D
Total caps = 14
Probability = 5c0 * 9c3/ 14c3 = 3/13
Friday, September 27, 2019
Quant Test for IBPS PO Prelims Exam set – 12
Directions(1-5): What value will come in place of question mark '?' in the following questions.
Labels:
Sectional Tests
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