- I.15x^2 – 16x + 4 = 0
II.4y^2 – 19y + 12 = 0
y >= xx >= yy > xx > yNo relationOption C
I.15x^2 – 16x + 4 = 0
=>15x^2 – 10x – 6x + 4 = 0
=>(3x-2)(5x-2) = 0
=>x = 2/3,2/5
II.4y^2 – 19y + 12 = 0
=>4y^2 – 16y – 3y + 12 =0
=>(4y-3)(y-4) = 0
=>y = ¾,4
y > x
- I.x^2 – 8x + 15 = 0
II.y^2 – 13y + 42 = 0
y >= xx > yx >= yy > xNo relationOption D
I.x^2 – 8x + 15 = 0
=>x^2 – 3x – 5x + 15 = 0
=>(x – 3)(x – 5) = 0
=>x = 3,5
II.y^2 – 13y + 42 = 0
=>y^2 – 7y – 6y + 42 =0
=>(y -7)(y – 6) = 0
=>y = 7,6
y > x
- I.x^2 – 20x + 96 = 0
II.y^2 – 13y + 40 = 0
y >= xNo relationy > xx >= yx > yOption D
I.x^2 – 20x + 96 = 0
=>x^2 – 12x – 8x + 96 = 0
=>(x-8)(x – 12) = 0
=>x = 8,12
II.y^2 – 13y + 40 = 0
=>y^2 – 8y – 5y + 40 = 0
=>(y-8)(y-5) = 0
=>y = 8,5
x >= y
- I.5x^2 – 27x + 10 =0
II.y^2 – 14y + 48 = 0
x > yNo relationy > xy >= xx >= yOption C
I.5x^2 – 27x + 10 =0
=>5x^2 – 25x – 2x + 10= 0
=>(x-5)(5x - 2) = 0
=>x = 5,2/5
II.y^2 – 14y + 48 = 0
=>y^2 -8y – 6y + 48 = 0
=>(y - 8)(y-6) = 0
=>y = 8,6
y > x
- I.7x + 5y = 63
II.5x + 3y = 41
y >= xx > yy > xx >= yNo relationOption C
On solving both the equations, we get
x = 4
y = 7
y > x
Directions(6-10): Answer the questions based on the following information.
The given chart shows the expenditure and savings (in Rs.) of Suraj in different months.
Income = Expenditure + Savings
- Income of Suraj in January is what percentage more or less than the expenditure of Suraj in same month?
80%68%66%75%70%Option D
Income in January = 2400+1800 = Rs.4200
Percentage = [(4200-2400)/2400]*100 = 75%
- Find the ratio of expenditure of Suraj in March to the savings of Suraj in March.
10:91:24:36:55:7Option D
Required ratio = 3000:2500 = 6:5
- Income of Suraj in May is how much more than income of Suraj in January.
Rs.2200Rs.2500Rs.2600Rs.2100Rs.2800Option E
Income of January = 2400+1800 = Rs.4200
Income of March = 4500+2500 = Rs.7000
Difference = 7000 – 4200 = Rs.2800
- Income of Suraj in June is 25% more than the income of Suraj in April, and the respective ratio of expenditure to savings in June is 3:2. Find the savings of Suraj in June.
Rs.4200Rs.3900Rs.2800Rs.3100Rs.2000Option C
Income of Suraj in April = 3600+2000 = Rs.5600
Income of Suraj in June = 5600*1.25 = Rs.7000
Savings in June = 2/5*7000 = Rs.2800
- Find the average of the income of Suraj in February, March and May taken together.
Rs.4000Rs.6100Rs.4500Rs.5800Rs.5000Option D
Average = (5000+5400+7000)/3 = Rs.5800
Wednesday, September 25, 2019
Quant Test for IBPS PO Prelims Exam set – 10
Directions(1-5): Find the values of x and y and compare their values and choose a correct option.
Labels:
Sectional Tests
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