- 39.95% of 265 + 35.2% of 178 = 50% of ? + ?% of 80
180150100140130Option E
39.95% of 265 + 35.2% of 178 = 50% of ? + ?% of 80
=> 106 + 63 = 0.5 ×?+ ?/100 × 80
=> 16900 = 130 ×?
=> ?= 130
- 15.5% of 849 + 24.8% of 651 = ?
300295395250288Option B
15.5% of 849 + 24.8% of 651 = ?
=> ?= 131.75+ 161.2 = 292.95 ≈ 295
- 2(1/6) + [3(3/4) – 1(1/4)] =?
4(9/5)6(2/7)3(1/3)4(2/3)4(5/8)Option D
2(1/6) + [3(3/4) – 1(1/4)] =?
=>4 + (2+9-3)/12 = ?
=>? = 4(2/3)
- 7(3/6)of 534 + 262 = 61800 – ?
5264352460575335252052400Option C
7(3/6)of 534 + 262 = 61800 – ?
=>45/6*534 + 262 = 61800 - ?
=>? = 57533
- 72% of 486 – 64% of 261 = ?
190177183175166Option C
72% of 486 – 64% of 261 = ?
=> 349.92 – 167.04 = 182.88 == 183
- A can complete a work in 36 days. B is 33.33% more efficient than A. In how many days both complete the work if they work on alternate days starting with A?
2036392531Option E
B will complete the work alone in = 3/4 × 36 = 27 days
A -36 ------3
-------108
B — 27------ 4
Let total units of work = 108
No. of units done by A in 1 day = 3
No. of units done by B in 1 day = 4
Total work done in 2 days = 7 units
Work done in 30 days = 7 × 15 = 105 units
Remaining work will be done by A in [108 - 105]/3 = 1 day.
Total days taken = 31 days
- Harsh adds 12% of his salary in PPF. 3/8th of the remaining amount is spent on clothes and the difference between PPF and clothes expenses is Rs 10500. Remaining amount is spent on house rent and other expenses. If house rent expenses is Rs 1500 less than other expenses, then what is the house rent expenses?
1000013000180001670015500Option B
12% of the salary is added as PPF. Remaining Part = 100 - 12 = 88%
Amount spent on clothes = 3/8 of 88% = 33%
Difference between PPF and cloth expanses = 33 - 12 = 21% of salary = 10500
Total salary = 50000
Other expanses = House Rent expanses + 1500
House Rent expanses + Other expanses = (100 - 33 - 12)% of salary = 55% of salary = 27500
House Rent expanses + House Rent expanses + 1500 = 27500
2 × House Rent expanses = 27500 - 1500 = 26000
House Rent expanses = 13000
- The surface area of a spherical part of a hemispherical bowl with a flat circular detachable cover, excluding the cover, is 616 sq cm. The area of the cover is 38.5 sq cm. What is the volume of the bowl?
23561230200020331958Option D
2*pi*r*r = 616
=>r^2 = (616/2)*(7/22)
=>r^2 = 98
Volume = 2/3*pi*r^3
= 2033 cm^3
- A vessel contains liquid P and Q in the ratio 5 : 3. If 16 litres of the mixture are removed and the same quantity of liquid Q is added, the ratio become 3 : 5. What quantity does the vessel hold?
5030402010Option C
Let, the quantity of liquid P and Q be 5x and 3x litres respectively.
Quantity of P removed = 5/(5+3) × 16 = 10 litres
Quantity of Q removed = 3/(5+3) × 16 = 6 litres
Now, (5𝑥−10)/(3𝑥−6+16 )= 3/5
⇒ 25𝑥 − 50 = 9𝑥 + 30
⇒ 16𝑥 = 80
⇒ 𝑥 = 5
Quantity that vessel hold = 8 ×5 = 40 litres
- In bag A there are 5 red balls, X green balls and 7 yellow balls. Probability of drawing one green ball from bag A is 2/5. In bag B there are (X-3) red balls, (X-4) green balls and 6 yellow balls. 2 balls are drawn from bag B. Find the probability that both the balls are red colour?
1/153/146/192/213/17Option D
Probability of drawing one green ball = x/(x+12) = 2/5
⇒ x = 8
Required probability = 5C2/15C2 = 2/21
Thursday, September 26, 2019
Quant Test for IBPS PO Prelims Exam set – 11
Directions(1-5): What will be the value of question mark '?' in place of question mark.
Labels:
Sectional Tests
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