Quant Test for IBPS PO Prelims Exam set – 4

Directions(1-5): What approximate value will come in place of question mark '?' in the following questions.

1. 42*5.12/2.99 + 49.89 = ?*1.99
   54
   84
   60
   50
   78
   Option C
   42*5.12/2.99 + 49.89 = ?*1.99
   =>42*5/3 + 50 = ?*2
   =>70+50 = ?*2
   =>? = 60
   
   
    



2. 18.18*3.99 *(135.003 / 26.87) – (15.001*3.89) = ?
   356
   378
   313
   300
   389
   Option D
   18.18*3.99 *(135.003 / 26.87) – (15.001*3.89) = ?
   =>18*4 *(135/27) – (15*4) = ?
   =>72*5 – 60 = ?
   =>? = 360 -60
   =>? = 300
   
   
    



3. 30.01*(1024)^1/2 + 196 = ?^2 – 287
   30
   38
   44
   50
   61
   Option B
   30.01*(1024)^1/2 + 196 = ?^2 – 287
   =>30*32 + 196 = ?^2 – 287
   =>960 + 196 = ?^2 – 287
   =>?^2 = 1444
   =>? = 38
   
   
    



4. 35.2% of 1599 = ? – (449.92/6.12)*2
   759
   700
   647
   652
   770
   Option B
   35.2% of 1599 = ? – (449.92/6.12)*2
   =>35% of 1600 = ? – (450/6)*2
   =>560 = ? – 75*2
   =>560 = ? – 150
   =>? = 700
   
   
    



5. 16.12 * 15.94 + 654.92 – 344.84 = ?*5.93
   88
   82
   90
   78
   94
   Option C
   16.12 * 15.94 + 654.92 – 344.84 = ?*5.93
   =>16*16 + 655 – 345 = ?*6
   =>256 + 655 – 345 = ?*6
   =>? = 90
   
   
    



6. A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
   3.05 hrs.
   2.17 hrs.
   1.25 hrs.
   2.14 hrs.
   3.05 hrs.
   Option C
   Downstream =(1x 60)/10 = 6 kmph
   Rate upstream = 2 km/hr.
   Speed in still water =(6 + 2) /2= 4 kmph
   Time = 5/4 = 1.25 hrs.
   
    



7. In a right angled triangle smallest side of is 13 cm less than the side of a square of perimeter 72 cm. Second largest side of the right angled triangle is 2 cm less than the length of the rectangle of area 112 cm² and breadth 8 cm. What is the largest side of the right angled triangle?
   17 cm
   10 cm
   13 cm
   12 cm
   19 cm
   Option C
   Side of square = 72/4 = 18 cm
   Smallest side of the right angled triangle = 18 – 13 = 5 cm
   Length of rectangle = 112/8 = 14 cm
   Second side of the right angled triangle = 14 – 2 = 12 cm
   Hypotenuse of the right angled triangle = √(25 + 144) = 13 cm
   
   
    



8. 3 years ago, the average age of A, B, and C was 27 years. Also 5 years ago, the average age of B and C was 20 years. What is the present age of A?
   20
   40
   50
   80
   90
   Option B
   Sum of ages of A+B+C 3 yrs ago = 27*3 = 81
   After 3 yrs, i.e. at present their total = 81 + 3*3 = 90
   Similarly sum of present age of B&C = 20*2 +5*2 = 50
   Present age of A = 90-50 = 40
   
   
    



9. If the difference between the simple interest and compound interests on some principal amount at 20% for 3 years is Rs. 48, then the principal amount is:
   Rs. 327
   Rs. 313
   Rs. 320
   Rs. 300
   Rs. 375
   Option E
   Sum = Difference x (100)^3
   r^2(300 + r)
   = 48 x (100)^3
   20^2 (300 + 20)
   = Rs. 375
   
   
    



10. In a team of 6 boys and 8 girls, 5 students have to be selected. In how many ways it can be done so that at least 2 boys are included.
    1748
    1947
    1379
    1526
    1500
    Option D
    No. of ways = 6c2*5c3 + 6c3*5c2 + 6c4*5c1 + 6c5 = 1526