- [(๐๐) ^๐ ÷ ๐๐ × ๐๐] ÷ ๐๐ = ๐ ×?
2022182410Option C
[(๐๐) ^๐ ÷ ๐๐ × ๐๐] ÷ ๐๐ = ๐ ×?
=>7 ×? = 84×84/28 × 12 × 1/24
=> ? = 18
- (7.9% of 134) – (3.4% of 79) =?
12810613Option B
(7.9% of 134) – (3.4% of 79) =?
? = 7.9/100 × 134 − 3.4/100 × 79
= 7.9 == 8
- [(๐๐๐)^ ๐ ÷ ๐๐ × ๐๐] ÷ ๐๐ = √?
8449087389810208930082944Option E
[(๐๐๐)^ ๐ ÷ ๐๐ × ๐๐] ÷ ๐๐ = √?
=>√? = 36864/64 × 24 × 1/48 = 288
=> ? = 82944
- 30% of ๐/๐ of ๐/๐ of ๐/๐ of ๐/๐ of 9450 =?
4642444048Option E
30% of ๐/๐ of ๐/๐ of ๐/๐ of ๐/๐ of 9450 =?
=>? = 30/100 × 2/7 × 2/9 × 2/5 × 2/3 × 9450
= 48
- (๐/๐๐๐๐)^( −๐/๐) + ( ๐/๐๐๐)^( −๐/๐) = ? × 5
1813101517Option B
(๐/๐๐๐๐)^( −๐/๐) + ( ๐/๐๐๐)^( −๐/๐) = ? × 5
=>?× 5 = (4)^{( −5)×( −2/5)} + (7) ^{(−3)×( −2/ 3)}
=> ? = (16+49)/5 = 13
- 3.5% of 40 + 3.5% of 80 =? % of 10
4045484246Option D
3.5% of 40 + 3.5% of 80 =? % of 10
=>? = (1.4 + 2.8)/10 × 100 = 42
- ๐( ๐/๐) + ๐(๐/๐) + ๐(๐/๐) – ๐(๐/๐) = ?
1(15/41)3(11/46)4(16/45)3(10/45)4(16/41)Option C
๐( ๐/๐) + ๐(๐/๐) + ๐(๐/๐) – ๐(๐/๐) = ?
? = (1 + 2 + 3 − 4) + ( 7/9 + 5/3 + 1/9 – 1/5 )
= 2 + 106/45 = 4(16/45)
- (๐ × ๐)^๐ ÷ (๐ × ๐)^๐ × (๐๐ × ๐)^๐ = (๐)^?
35267Option B
(๐ × ๐)^๐ ÷ (๐ × ๐)^๐ × (๐๐ × ๐)^๐ = (๐)^?
=>(6)^? = (6) ^3 ÷ 6^4 × 6^6
⇒ (6)^? = 6^(3−4+6)
⇒ ? = 5
- ๐๐๐. ๐๐ − ๐๐๐. ๐๐ + ๐๐๐. ๐๐ − ๐๐. ๐๐ = ?
104110100107117Option A
๐๐๐. ๐๐ − ๐๐๐. ๐๐ + ๐๐๐. ๐๐ − ๐๐. ๐๐ = ?
? = 576.03 – 472.31 = 103.72
== 104
- √๐๐๐ ÷ (๐)^๐ × ๐. ๐ + (๐)^๐ − ๐๐๐ = ?
110111120127123Option E
√๐๐๐ ÷ (๐)^๐ × ๐. ๐ + (๐)^๐ − ๐๐๐ = ?
= ? = 24 ÷ 16 × 7.4 + 343 − 231
= 11.1 + 112 = 123.1 == 123
Friday, August 30, 2019
Quantitative Aptitude: Simplification Questions Set 79
Directions(1-10): What approximate value will come in place of question mark '?' in the following questions.
Labels:
Quantitative Aptitude
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