Mixed Quantitative Aptitude Questions Set 160

1. When a person sold an article, his profit percent is 60% of the selling price. If the cost price is increased by 75% and the selling price remains the same, then find decrement in the profit is what percent of the selling price of the article?
   50%
   40%
   10%
   30%
   20%
   Option D
   Let the selling price be 250x
   Profit = 150x CP=250x − 150x = 100x
   Now, new C.P. = 100x × 175 100 = 175x
   New S.P. = 250x
   New profit = 250x – 175x = 75x
   Required % = [(150x−75x)/250x] × 100 = 30%
   
   
    



2. An article is marked 6(2/3)% above the cost price and loss incurred on selling that article is 25% of the discount given on it. Then, find the discount % given?
   50(1/3)%
   52(1/5)%
   51(1/4)%
   53(1/3)%
   50(1/2)%
   Option D
   Let the cost price be Rs 3x Then the marked price= Rs 5x
   And let the discount given be Rs 4y
   Loss incurred= Rs y
   3x − y = 5x − 4y
   3y = 2x
   Marked price=Rs 15/2 y
   Required discount % = 4y*2/15y × 100 = 53(1/3)%
   
   
    



3. A train travelling at 72 km/hr. classes a platform of 160 m in 18 second and another train travelling at 90 km/hr crosses the same platform in 15 second. Find the length of another train?
   205 m
   250 m
   215 m
   220 m
   200 m
   Option C
   Speed of 1st train = 72 × 5 18 = 20 m/s
   Distance travelled by 1st train = 20 × 18 = 360 m
   Length of train (1st) = 360 – 160 = 200 m
   Speed of 2nd train = 90 × 5 18 = 25 m/s
   Distance travelled = 25 × 15 = 375 m
   Length of 2nd train = 375 − 160 = 215 m
   
   
   
    



4. If A start from P with speed 60 km/hr at 8:00 am and B starts with speed 70 km/hr. at 8 : 30 am from Q and total distance between P and Q is 680 km, find at what time they will cross each other?
   1 : 00 pm
   2 : 10 pm
   3 : 15 pm
   1 : 30 pm
   2 : 30 pm
   Option D
   Dist travelled by A in 1 2 hr = 30 km
   Remaining distance to be covered = 680 – 30 = 650 km
   Relative Speed = 60 + 70 = 130
   Time taken = 650 130 = 5 hr
   Time = 8 : 30 + 5 hr = 1 : 30 pm
   
   
    



5. If a person invested 6000 at T% S.I for 3 year and same amount at (T + 5)% CI for 2 year and difference between both interest is 60 Rs. then find T (in %)?
   13%
   15%
   18%
   12%
   10%
   Option B
   By going with the options Interest received at SI = 6000 × 3 × 15 100 = Rs.2700
   T + 5 = 20%
   Interest received after 2 yrs at CI = 6000 × 44/100 = 2640
   Difference = 2700 – 2640 = Rs.60
   T = 15%
   
   
    
Directions(6-10): What will come in place of question mark "?" in the following questions.


6. 623898 × 99 = ? × 60,000
   1200
   1000
   1100
   1030
   1350
   Option D
   623898 × 99 = ? × 60,000
   ? = (623898 × 99)/60000
   = 624000 × 100/600000 == 1030
   
   
    



7. √𝟔𝟐𝟒. 𝟗1 + (𝟒. 8)^1/𝟐 =? ÷ 𝟏𝟒.𝟗
   10
   5
   7
   12
   14
   Option A
   √𝟔𝟐𝟒. 𝟗1 + (𝟒. 8)^1/𝟐 =? ÷ 𝟏𝟒.𝟗
   √625 + 5^2 =?÷ 15
   ⇒ 25 + 25 =?× 5
   => ? = 50/5 = 10
   
   
    



8. 564.666 + 82.5091 × 44.581 – 34.111 = ?
   4225
   4210
   4400
   4141
   4000
   Option B
   564.666 + 82.5091 × 44.581 – 34.111 = ?
   = 565 + 82 × 45 – 34 = 4250 = 4210
   
   
    



9. (47% of 1442 – 36% of 1412) ÷ 63 = ?
   4
   5
   3
   6
   7
   Option C
   (47% of 1442 – 36% of 1412) ÷ 63 = ?
   (47% × 1442 − 36% × 1412)/63
   = [(1440 × 45)/100 – (35 × 1410)/100]/60
   = (648 − 493.5)/60 = 3
   
   
    



10. (341789 + 265108) ÷ (8936 – 3578) = ?
    100
    113
    110
    125
    120
    Option B
    (341789 + 265108) ÷ (8936 – 3578) = ?
    = (341789 + 265108)/(8936 – 3578) = 606897/5358
    = 606900/5360 = 113