Mixed Quantitative Aptitude Questions Set 145

Directions(1-5): Table given below shows the data of students and teachers of different branches in an engineering college. Study the below mentioned table carefully to answer the following questions.

1. Number of teachers in Chemical branch is what percent of number of students in Mechanical branch?
   
   
   2(3/8) %
   5(3/7) %
   2(5/9) %
   1(3/8) %
   5(5/9) %
   Option E
   Let number of students and teachers in Chemical branch be ‘13x’ & ‘x’ respectively.
   So, 13x – x = 168
   x = 14
   And number of teachers in Chemical branch = x = 14
   Let number of students and teachers in mechanical branch be 21y & 2y respectively.
   So, 21y – 2y = 228
   19y = 228
   y = 12
   Required Percentage = 14/252 × 100 = 5(5/9) %
   
   
    



2. If the ratio of number of boys to number of girls in Civil branch is 4 : 3, then find number of girls in Civil branch is what percent of number of teachers in that branch?
   139(1/2)%
   122(2/5)%
   130(1/7)%
   139(2/7)%
   112(1/5)%
   Option D
   Let number of students & teachers in Civil branch be ‘13x’ and ‘4x’ respectively.
   So, 13x – 4x = 126
   x = 14
   Hence, number of students in Civil branch = 13x = 182
   Number of teachers in Civil branch = 4x = 56
   Now, Number of girls in Civil branch = 182 × 3/7 = 78
   Required % = 78/56 × 100 = 975/7 % = 139(2/7)%
   
   
    



3. Find the ratio of number of students in I.T. and Electrical branch together to number of teachers in I.T. and Electrical branch together.
   40 : 3
   41 : 6
   43 : 16
   42 : 7
   49 : 3
   Option B
   Let number of students & teachers in I.T. branch be ‘19x’ & ‘3x’ respectively.
   So, 19x – 3x = 256
   x = 16
   Hence, number of students in I.T. branch = 19x = 304
   And number of teachers in I.T. branch = 3x = 48
   Let number of students & teaches in Electrical branch be ‘15y’ & ‘2y’ respectively.
   So, 15y – 2y = 234
   y = 18
   Hence, number of students in Electrical branch = 15y = 270
   And number of teachers in Electrical branch = 2y = 36
   Now, Required ratio = (304 + 270)/(48 +36) = 574:84 = 41 : 6
   
   
    



4. Number of teachers in I.T. branch is how much more or less than number of teachers in Chemical branch?
   30
   21
   24
   34
   28
   Option D
   Let number of teachers & students in I.T. branch be ‘3x’ & ‘19x’ respectively.
   So, 19x – 3x = 256
   x = 16
   So, number of teachers in I.T. branch = 3x = 48
   Let numbers of teacher and students in Chemical branch be ‘y’ & ‘13y’ respectively.
   So, 13y – y = 168
   y = 14
   Hence, number of teachers in Chemical branch = y = 14
   Required difference = 48 – 14 = 34
   
   
    



5. Number of students in Mechanical branch is what percent of number of students in Computer Science branch?
   75%
   70%
   77%
   80%
   84%
   Option E
   Let number of students & teachers in Computer Science branch be ‘12x’ & ‘x’ respectively.
   So, 12x – x = 275
   x = 25
   So, number of students in Computer Science branch = 12x = 300
   Now, let number of students & teachers in mechanical branch be ‘21y’ & ‘2y’ respectively.
   So, 21y – 2y = 228
   y = 12
   Hence, number of students in Mechanical branch = 21y = 252
   So, required % = 252/300 × 100 = 84%
   
   
    
Directions(6-10): Find the missing term '?' of the following series.


6. 210, 130, 60, ?, 6, 2
   30
   21
   25
   22
   26
   Option A
   6^3−6,5^3+5,4^3−4,3^3+3,2^3−2,1^3+1
   3^3+3=30
   
   
    



7. 6 ,15, 45, 157.5, ?, 2835
   600
   550
   525
   630
   515
   Option D
   ×2.5,× 3,× 3.5,× 4
   157.5 × 4 = 630
   
   
    



8. 567,1140, 2290, ?, 9206, 18434
   4594
   4250
   4000
   4128
   4424
   Option A
   ×2 + 6,×2 + 10,× 2 + 14,× 2+ 18
   2290×2 +14 = 4594
   
   
    



9. 17, 38, ?, 508,2565,15426
   100
   115
   123
   120
   125
   Option C
   ×2+ 2^2,×3+3^2,× 4 + 4^2
   38×3 +3^2 = 123
   
   
    



10. 2, 60,10, 120, 30, ?
    200
    220
    225
    222
    210
    Option E
    1^3+1, 4^3 – 4,2^3+2,5^3 –5,3^3+3,6^3 – 6
    6^3−6 = 210