Mixed Quantitative Aptitude Questions Set 154

1. Two partners invest Rs 12500 and Rs 8500 respectively in a business and agree that 60% of the profit should be divided equally between them and the remaining profit is to be divided in the ratio of their capital. If one partner gets Rs 240 more than the other, find the total profit made in the business.
   
   
   3113
   3000
   3500
   3300
   3150
   Option E
   (Profit of A) : (Profit of B) = 12,500 : 8,500 = 125 : 85 = 25 : 17
   40% of total profit = 240 × (25 + 17)/(25 − 17) = 1260
   100% profit = 1260/40 × 100 = 3150
   
   
    



2. Aman invests a certain sum in scheme A at compound interest (compounded annually) of 10% per annum for 2 years. In scheme B he invests at simple interest of 8% per annum for 2 years. He invests in schemes A and B in the ratio of 1 : 2.The difference between the interest earned from both the schemes is Rs 990. Find the amount invested in scheme A.
   8900
   7890
   9000
   7007
   9008
   Option C
   Let in both schemes he invested Rs. P and 2P respectively.
   ATQ, |P [(1 + 10/100)^2 − 1] – (2P × 8 × 2)/100 | = 990
   ⇒ | 21P/100 − 32P/100| = 990
   ⇒ P = 99000/11
   ⇒ P = 9000
   
   
    



3. X’s age 3 years ago was three time the present age of Y. At present, Z’s age is twice the age of Y. Also, Z is 12 years younger than X. What is the present age of Z?
   10
   15
   14
   18
   12
   Option D
   Let present ages of all the three are X, Y and Z respectively.
   X = 3Y + 3 …(i)
   Z = 2Y …(ii)
   X = Z + 12 …(iii)
   From equations (i), (ii) and (iii)
   X – 3Y = 3 and X – 2Y = 12
   After solving these two resultant equations, we get
   Y = 9 years
   Z’s present age = 18 years.
   
   
    



4. A bag contains 4 red balls, 6 green balls and 5 blue balls. If three balls are picked at random, what is the probability that two of them are green and one of them is blue in colour?
   10/97
   13/92
   11/90
   15/91
   17/93
   Option D
   Required probability = 6C2 × 5C1/ 15C3 = 15/91
   
    



5. A bag contains 5 red balls, 6 yellow and 3 green balls. If two balls are picked at random, what is the probability that both are red or both are green in colour?
   1/3
   1/4
   1/7
   1/9
   1/2
   Option C
   Required probability = 5C2/ 14C2 + 3C2/14C2 = 10/91 + 3/91 = 13/91 = 1/7
   
    
Directions(6-10): Find the missing term '?' of the following series.


6. 282, 286, 302, ?, 402, 502
   300
   317
   338
   320
   313
   Option C
   +(2)^2, +(4)^2, +(6)^2, +(8)^2, +(10)^2
   ? = 338
   
   
    



7. 2187, 729, 243, 81, 27, 9, ?
   4
   6
   5
   3
   7
   Option D
   /3,/3,/3,/3,/3,/3
   ? = 3
   
   
    



8. 384, 381, 372, 345, 264, ?
   21
   29
   23
   27
   25
   Option A
   -3,-9,-27,-81,-243
   ? = 21
   
   
    



9. 5, 9, 18, 34, 59, 95, ?
   120
   144
   163
   135
   170
   Option B
   +2^2,+3^2,+4^2,+5^2,+6^2,+7^2
   ? = 144
   
   
    



10. 8, 15, 36, 99, 288, ?
    800
    891
    828
    855
    885
    Option D
    +7,+21,+63,+189,+567
    ? = 855