- 3, 4, 9, 28, 113, 565, 3397
9113565284Option C
*1+1
*2+1
*3+1
*4+1
*5+1
*6+1
566 in place of 565.
- 4, 6, 12, 30, 60, 315, 1260
126063151260Option B
*1.5,*2,*2.5,*3,*3.5,*4
90 in place of 60.
- 1, 730, 975, 1054, 1081, 1090, 1093
105473010811090975Option E
- 9.2, 10.6, 7.6, 12.4, 6, 14, 4.4
11.212.513.910.614.6Option D
+1.6,-3.2,+4.8,-6.4,+8,-9.6
10.8 in place of 10.6.
- 200, 196, 192, 180, 160, 130, 88
196200180130160Option A
Double difference
198 in place of 196.
- A man invested Rs. 8000 in a scheme giving 20% p.a. compound interest for two year. The interest received from this scheme is 400% more than the interest on some other amount from another scheme giving 8% S.I. for 4 year. Find the total amount invested in both schemes.
11,00010,20012,50015,20012,120Option B
CI earned in 2 years = 8000[(1+20/100)^3 - 1] – 8000
= 3520
Let amount invested in another scheme is Rs.P.
3520 = 500% of P*8*4/100
=>P – [3520*100]/[32*5]
=>P = 2200
Total investment = 8000+2200 = 10,200
- Radius of a cylinder is equal to the side of an equilateral triangle having area cm² and height of the cylinder is equal to the perimeter of the triangle. Then find the volume of cylinder.
1782*pi1126*pi1536*pi1440*pi1661*piOption C
Radius of cylinder = side of equilateral Δ
(3)^1/2/4 a^2 = 16(3)^1/2
a² = 64
=>a = 8 cm
And, height of cylinder = 3 × 8 = 24 cm
Volume of cylinder = πr²h
= π × 8² × 24
= 1536 π cm³
- Sum of present ages of A and B is 41. Age of A 2 year hence is equal to age of C, 1 year ago. Age of A, 4 year hence is equal to age of B 1year ago and ratio of present age of A and D is 3 : 4. Find the difference of age of C and D.
25743Option E
A + B = 41 …(i)
C -1 = A + 2
C = A + 3
And
A + 4 = B - 1
⇒ B = A + 5 …(ii)
From (i) + (ii)
A = 18 years
B = 18 + 5 = 23 years
C = 18 + 3 = 21 years
D = = 24 years
Required difference = 24 – 21 = 3 years
- The surface area of a spherical part of a hemispherical bowl with a flat circular detachable cover, excluding the cover, is 616 sq cm. The area of the cover is 38.5 sq cm. What is the volume of the bowl?
2636.122302.151928.612172.122032.69Option E
2*pi*r*r = 616
=>r^2 = 616/2*7/22
=>r^2 = 98
Volume = 2/3 *pi*98*7(2)^1/2 = 2032.69 cm^3
- In one litre of mixture of alcohol and water, 30% is water. The amount of alcohol that must be added to the mixture, so that the part of water in the mixture becomes 15%, is:
14521000110012341340Option B
300/(1000+x)*100 = 15
=>x = 1000 ml
Saturday, July 20, 2019
Mixed Quantitative Aptitude Questions Set 148
Directions(1-5): Find the wrong term of the following series.
Labels:
Quantitative Aptitude
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