Mixed Quantitative Aptitude Questions Set 152

1. 36% of 245 − 40% of 210 = 10 − ?
   4.4
   3.2
   6.5
   5.8
   2.9
   Option D
   36% of 245 − 40% of 210 = 10 − ?
   =>? = 10 – 88.2 + 84 = 5.8
   
   
    



2. 3( 1/7 ) + 2( 3/5) + 𝟕( 1/5) – 5(3/7)− 18/35 = 35/?
   3
   7
   2
   5
   4
   Option D
   3( 1/7 ) + 2( 3/5) + 𝟕( 1/5) – 5(3/7)− 18/35 = 35/?
   35/? = 263/35 – 18/35
   => ? = 35×35/245 = 5
   
   
    



3. √1225 ÷ (343)^1/3 × 45% of 760 = ?
   1727
   1820
   1893
   1989
   1710
   Option E
   √1225 ÷ (343)^1/3 × 45% of 760 = ?
   ? = 35 ÷ 7 × 342 = 1710
   
   
    



4. 175% of 460 + 110% of 170 + 2^? = 1000
   7
   2
   1
   5
   3
   Option E
   175% of 460 + 110% of 170 + 2^? = 1000
   =>2^? = 1000 − 805 − 187 = 8
   => ? = 3
   
   
    



5. 18^7.9 × 3^0.1 × 6^0.1 ÷ (3^4 × 6^4) = 18^?
   4
   2
   3
   1
   5
   Option A
   18^7.9 × 3^0.1 × 6^0.1 ÷ (3^4 × 6^4) = 18^?
   =>18^? = 18^7.9 × 18^0.1 ÷ 18^4
   => ? = 4
   
   
    



6. Cost price of article A is double then that of article B and shopkeeper mark up both the article 20% more than the cost price. If at the time of sale shopkeeper gave Rs. 9 discount and earn 17% profit on total. Find the cost price of article A?
   263
   368
   289
   345
   200
   Option E
   Let C.P. of A = 2x
   C.P. of B = x
   Total cost price = 3x
   Mark up price = 3x × 12/10 = 3.6x
   ATQ, 3.6x – 9 = 3x × 1.17
   ⇒ 3.6x – 3.51x = 9
   ⇒ 0.09x = 9
   ⇒ x = 100
   C.P. of article A = 200
   
   
    



7. Ravi invested Rs 18000 in scheme ‘A’ which offers 15% p.a. at simple interest and Rs 15000 in scheme ‘B’ which offers 18% p.a at compound interest. Find the difference between the interest earn from these two schemes after two years?
   400
   440
   450
   452
   486
   Option E
   Interest earn from scheme ‘A’ = 18000 × 15 × 2/100 = 5400
   Interest earn from Scheme ‘B’ = 15000 [(1 + 18/100)^2 − 1] = 15000 [ 3924/10000] = 5886
   Required difference = 5886 – 5400 = 486
   
   
    



8. A tank can be filled with water by two pipes A and B together in 36 minutes. If the pipe B was closed after 30 minutes, the tank is filled in 40 minutes. The pipe B can alone fill the tank in?
   50
   70
   60
   80
   90
   Option E
   In 30 min the part of the tank will be filled by both tap = 30/36 = 5/6
   Required tap = 1 – 5/6 = 1/6
   1/ 6 part of the tank will be filled by tank A in 10 min.
   ∴ tap A will take 60 min.
   ∴ tap B will take time to fill the tank = 1/36 – 1/60 = 1/90
   Required time = 90 min.
   
   
    



9. 40 men, working 8 hours a day can do a piece of work in 15 days. Find the number of days in which second group of 60 men working 4 hrs a day can do twice the work. Assume that 3 men of the first group do as much work in 2 hour as 4 men of the second group do in 3 hrs.
   70
   60
   80
   50
   100
   Option C
   Let efficiency of men of first group is M1 and second group is M2
   3M1 × 2 = 4M2 × 3
   M1 = 2M2
   work = 40M1 × 8 × 15
   According to question,
   40M1 × 8 × 15 × 2 = 60M2 × 4 × d
   d = 80 days
   
   
    



10. An alloy of copper and aluminum has 40% copper. Another alloy of Copper and Zinc has Copper and Zinc in the ratio 2: 7. These two alloys are mixed in ratio 5:3. Quantity of aluminum is what percent more/less than the quantity of copper in final alloy.
    14.4%
    13.8%
    12.5%
    11.6%
    10.9%
    Option C
    Let quantity → 5x and 3x
    Quantity of copper in final alloy = 2/5 × 5x + 2/9 × 3x = 8x/3
    Quantity of Aluminium = 3/5 × 5x = 3x
    Required percentage = [3x – 8x/3]/ 8x/3 × 100 = 12.5%