- 1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
1.111.252.231.462.05Option D
1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
? = 0.81 + 0.49 + 0.16 = 1.46
- 39% of 450 + 51% of 340 – 40% of 255 =?
112.5230.6246.9201.8250.7Option C
39% of 450 + 51% of 340 – 40% of 255 =?
? = 39/100 × 450 + 51/100 × 340 – 40/100 × 255
= 246.9
- 17 × 25 – 240 +? ÷ 41 = 354
45405646506069296000Option D
17 × 25 – 240 +? ÷ 41 = 354
? /41 = 354 – 425 + 240
⇒ ? = 41 × 169
⇒ ? = 6929
- 3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
120.6100.7121.6130.8124.8Option E
3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
? /0.8 = 156
⇒ ? = 124.8
- ? ÷ 13 + 2262 ÷ 39 × 243 + 273 ÷ 3 = 5 × (1481 + 1376)
15001600120013001100Option D
? ÷ 13 + 2262 ÷ 39 × 243 + 273 ÷ 3 = 5 × (1481 + 1376)
? /13 + 14094 + 91 = 14,285
⇒ ?/13 = 100
⇒ ? = 1300
- A milkman has 20 L of pure milk. He sells 5 L of it at profit of 20% and he mixes 5 L water in remaining quantity of milk. If he sells whole quantity of mixture at cost price, then find his percentage profit?
36%20%30%15%10%Option C
Let 1 L of milk cost = Rs.10
So, in selling 5 L of milk he get = 1 5 × 5 × 10 Profit
If he professes to sell mixture at cost price then his profit = 5 × 10 Rs.
Overall percentage profit = (50+10)/( 20×10) × 100 = 30%
- The sum of the radius and height of a cylinder is 18m. The total surface area of the cylinder is 792 m², what is the volume of the cylinder ? (in m³)
13021552169416601545Option C
Given, h + r = 18 m
According to question,
2πr (h + r) = 792
2 × 22/7 × r × 18 = 792
r = 7m
And h= 11m
Volume of the cylinder = πr²h = 22/7 × 7 × 7 × 11 = 22 × 77 = 1694 m³
- In a 90 litre mixture of milk and water, percentage of water is only 30%. The milkman gave 18 litres of this mixture to a customer and then added 18 litres of water to the remaining mixture. What is the percentage of milk in the final mixture ?
71%62%49%56%60%Option D
Initial water = 30 100 × 90 = 27 L
And, milk = 90 – 27 = 63 L
Required percentage = [70/100 × (90 – 18)]/90 × 100 = 56%
- If the area of a circle is 616 𝐜𝐦^𝟐 , what would be the total surface area of a hemisphere having the same radius as the circle ?
15561848199016761562Option B
Radius of circle = √ 616×7/22 = 14 cm
Total surface area of hemisphere = 3πr 2 = 3 × 22/7 × 14 × 14 = 1848 cm^2
- There are two mixtures of honey and water, the quantity of honey in them being 40% and 75% of the mixture respectively. If 5 gallons of the first are mixed with 8 gallons of the second, what will be the ratio of honey to water in the new mixture ?
8:93:78:51:23:4Option C
Required ratio = [40/100 × 5 + 75/100 × 8]/[60/ 100 × 5 + 25/100 × 8]
= [2 + 6]/[3 + 2] = 8: 5
Wednesday, July 10, 2019
Mixed Quantitative Aptitude Questions Set 143
Directions(1-5): What approximate value will come in place of question mark '?' in the following questions:
Labels:
Quantitative Aptitude
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