Mixed Quantitative Aptitude Questions Set 183

1. The shopkeeper sold TV table for Rs. 2000 and incurred a loss. Had he sold the item for Rs. 3600, his gain would have been equal to three times of the amount of loss that he incurred. At what price should he sell the article to gain 20 %?
   
   
   Rs. 4000
   Rs. 2340
   Rs.1880
   Rs. 2890
   Rs. 2880
   Option E
   Loss = C.P – 2000
   
   Profit = 3600 – C.P
   
   Profit = 3*Loss
   
   3600 – C.P = 3 * [C.P – 2000]
   
   3600 – C.P = 3C.P – 6000
   
   9600 = 4C.P
   
   C.P = 9600/4 = Rs. 2400
   
   SP = 2400 * (120/100) = Rs. 2880
   
   
   
    



2. The sum of lengths of two express trains X and Y is 640 m. The speed of train X to that of train Y is in the ratio of 3 : 4. The time taken by train X and train Y to cross a pole is in the ratio of 4 : 5. Find the difference between the length of train X to that of Y?
   
   
   150 m
   160 m
   120 m
   130 m
   140 m
   Option B
   Let the length of train X be x m,
   
   So, the length of train Y = 640 – x
   
   The speed of train X to that of train Y is in the ratio = 3 : 4 (3y, 4y)
   
   Time = Length of train / Speed
   
   4 = x / 3y
   
   x = 12y -> (1)
   
   (640 – x) / 4y = 5
   
   640 – x = 20y
   
   640 – 12y = 20y
   
   640 = 32y
   
   y = 20
   
   The length of train x = x = 12 * 20 = 240 m
   
   The length of train Y = 640 – x = 640 – 240 = 400 m
   
   Required difference = 400 – 240 = 160 m
   
    



3. In still water the boat speed is 36 km/hr and the speed of stream is 12 km/hr. The time taken by boat to travel from X to Y downstream is 3 ½ hours less to travel from Y to Z upstream. If the distance between X to Y is 24 km more than the distance between Y to Z, then find the distance between X to Y?
   
   
   200 km
   216 km
   234 km
   116 km
   316 km
   Option B
   The speed of downstream = 36 + 12 = 48 km/hr
   
   The speed of upstream = 36 – 12 = 24 km/hr
   
   Let the distance between Y to Z be x km,
   
   The distance between X to Y = (x + 24) km
   
   Given,
   
   x / 24 – (x + 24) / 48 = 7/2
   
   (2x – x – 24) / 48 = 7/2
   
   x – 24 = 168
   
   x = 192
   
   The distance between X to Y = x + 24 = 192 + 24 = 216 km
   
   
   
    



4. Man 1 and 2 are 585 km away and both of them start moving towards each other at the same time. After some time when 1 has travelled 360 km he meets 2. What is the ratio of the speed of 1 to that of 2?
   
   
   8 : 11
   7 : 5
   8 : 9
   4 : 5
   8 : 5
   Option E
   Distance travelled by 1 when he met = 360 km
   
   Distance travelled by 2 when he met = 585 – 360 = 225 km
   
   The ratio of the speed of 1 to that of 2
   
   = > 360 : 225
   
   = > 8 : 5
   
   
   
    



5. Juice and water in a jar contains 32 liters Juice and 10 liters water. X liter of Juice and X liter of water is added to a new mixture. If 40 % of new mixture is 24 liters, then find the value of X (In liters)?
   
   
   5
   6
   7
   8
   9
   Option E
   40/100) * New mixture = 24
   
   New mixture = 24 * (5/2) = 60 liters
   
   Given,
   
   32 + X + 10 + X = 60
   
   42 + 2X = 60
   
   2X = 18
   
   X = 9
   
   
   
    


Directions (6-10): Following Radar graph shows the total number of Tulips in 5 different boxes and the blue Tulips in them.
Blue line-----> total tulips
Red line------> blue tulips

6. Find the difference between the average number of Tulips in the box A, B and C to the average number of Tulips other than the blue colour in the box B, D and E.
   25
   26
   27
   28
   29
   Option A
   Number of Tulips other than the blue colour in the box,
   B = 40 – 10 = 30
   D = 75 – 45 = 30
   E = 30 – 15 = 15
   The average = (30 + 30 + 15)/3 = 25
   Average number of Tulips in the box A, B and C =(60 + 40 + 50)/3 = 50
   Required difference = 50 – 25 = 25
   
   
    



7. Find the ratio of sum of Red color Tulips in A and D together to the pink color Tulips in same boxes, if the boxes have only three color Tulips and the ratio of pink and red color Tulips in the boxes A and D is 13: 7 and 4: 11 respectively.
   8: 17
   18: 37
   10: 17
   18: 10
   18: 17
   Option E
   Box A:
   Red + Pink = 60 – 20 = 40
   Red = (40/20) * 7 = 14
   Pink = (40/20) * 13 = 26
   Box D:
   Red + Pink = 75 – 45 = 30
   Red = (30/15) * 11 = 22
   Pink = (30/15) * 4 = 8
   Required ratio = (14 + 22): (26 + 8)
   = 18: 17
   
   
    



8. The boxes have only three color Tulips. The red color Tulips in the boxes B and C is what percentage of number of blue Tulips in the box D, if the grey and red color Tulips in the box B and C is in the ratio 3: 2 and 4: 3 respectively?
   20
   40
   60
   80
   85
   Option C
   Number of Tulips other than the blue colour in the box,
   B = 40 – 10 = 30
   Red Tulips in B = (30/5) * 2 = 12
   C = 50 – 15 = 35
   Red Tulips in C = (35/7) * 3 = 15
   Required percentage = [(12 + 15)/45] * 100 = 60%
   
   
    



9. The boxes have only three color Tulips. If the ratio of yellow color Tulips and pink color Tulips in the boxes is 3: 2, find the average difference between them.
   6
   7
   8
   9
   4
   Option A
   Number of Tulips other than the blue colour in the box,
   A = 60 – 20 = 40
   B = 40 – 10 = 30
   C = 50 – 15 = 35
   D = 75 – 45 = 30
   E = 30 – 15 = 15
   The sum = 40 + 30 + 35 + 30 + 15 = 150
   The ratio of yellow color Tulips and pink color Tulips in the boxes = 3: 2
   Yellow color Tulips = (150/5) * 3 = 90
   Pink color Tulips = (150/5) * 2 = 60
   Required difference = (90/5)- (60/5) = 30/5 = 6
   
   
    



10. Total number of blue Tulips in all the boxes together is approximately what percentage of total Tulips in all the boxes together?
    40%
    30%
    45%
    20%
    25%
    Option A
    Required % = [(20 + 10 + 15 + 45 + 15)/(60 + 40 + 50 + 75 + 30)] * 100
    = (105/255) * 100
    = 40%