Mixed Quantitative Aptitude Questions Set 181

1. The present age of Aisha is 12 years more the present age of Rahuman. After 5 years the ratio of ages of Rahuman and Aisha will be 3: 5, then find the age of Rahuman, after 2 years?
   10
   15
   20
   25
   30
   Option B
   Present age of Aisha = 12 + Present age of Rahul
   
   After 10 years, the ratio of ages of Rahuman and Aisha = 3: 5 (3x, 5x)
   
   5x – 3x = 12
   
   2x = 12
   
   x = 6
   
   The age of Rahuman, after 2 years = 3x – 5 + 2 = 15 years
   
    



2. The present age of N is twice the present age of P. The ratio between the present ages of Q and P is 7: 4. If the age of N after 6 years will be 30 years, then find the age of Q before 6 years?
   15
   20
   25
   30
   25
   Option A
   The ratio of present age of N and P = 2 : 1
   
   The ratio of present age of Q and P = 7 : 4
   
   The present age of N, P and Q = 8 : 4 : 7
   
   The age of N, after 6 years = 30 years
   
   The present age of N = 24 years
   
   8’s = 24
   
   1’s = 3
   
   The age of Q before 6 years = 7x – 6 = 15 years
   
    



3. Akil started the business investing Rs. 19000 and after 6 months Anush joined him with Rs. 28000. At the end of one year the total profit is Rs.16500.Akil’s profit share?
   
   
   
   
   4500
   5500
   7500
   8500
   9500
   Option E
   Akil’s share
   
   = > 19/33*16500
   
   = > Rs.9500
   
   
   
    



4. Akil started the business investing Rs. 19000 and after 6 months Anush joined him with Rs. 28000. At the end of one year the total profit is Rs.16500.Anush’s profit share?
   7000
   2000
   5000
   3000
   6000
   Option A
   = > 14/33 * 16500
   
   = > 7000
   
   
   
    



5. Two expresses running the same direction at the speed of 60kmph and 80kmph respectively. If the length of the expresses is 200m and 100m respectively, then find the time taken by first express crosses the second one?
   
   
   51
   52
   53
   54
   55
   Option D
   300 = (80-60) * (5/18) * x
   
   300 = 20 * (5/18) * x
   
   x = 54 seconds
   
   
   
    



6. The train 1 crosses the pole in 18 seconds at the speed of 60kmph and the train 1 crosses the 700m train 2 which is running opposite direction of train 1 at the speed of 20kmph, then find the time taken by train 1 crosses the another train?
   40
   45
   30
   35
   20
   Option B
   x = 60 * 5/18 * 18
   
   x = 300m
   
   300+700 = 80 * 5/18 * x
   
   x = 45 seconds
   
   
   
    



7. Time taken by A to complete 1/5th of work, if B takes 6 days to complete 3/5th of work and together they take 5 days to complete 3/4th of work?
   3
   4
   5
   6
   7
   Option B
   A and B completes 3/4th work in 5 days, so complete 1 work in 4/3 * 5 = 20/3 days
   
   B complete 3/5 work in 6 days, so complete work in 5/3 * 6 = 10 days
   
   So in 1 day A completes = 3/20 – 1/10 = 1/20
   
   So to complete 1/5th work = 1/5 * 20 = 4 days
   
   
   
    



8. Time taken by a Sadhapthi express to cross a plat form of length 60 km given that it crosses a pole in two and a half hours running at 60 km/hr?
   3
   3.5
   4
   4.5
   5
   Option B
   Length of train = 2.5 * 60 = 150 km
   
   So time taken to cross platform of length 60 km with speed 60 km/hr
   
   = (150+60)/60
   
   = 3.5 hrs
   
    



9. A bag contains 4 Red flowers, 3 white flowers, 5 orange flowers and 6 pink flowers. If two flowerss are drawn out randomly, then find the probability that both are either orange or pink?
   25 / 153
   15 / 153
   25 / 154
   12/ 153
   25 / 143
   Option A
   Total number of flowers = 4 + 3 + 5 + 6 = 18 flowers
   
   n(S) = 18C2
   
   Probability that both Orange or pink
   
   n(E) = 5C2 or 6C2
   
   P(E) = n(E) / n(S) = [5C2 or 6C2] / 18C2
   
   P(E) = 25 / 153
   
   
   
    



10. A bag contains 4 Red marbles, 3 white marbles, 5 orange marbles and 6 blue marbles. If four marbles are drawn out randomly, then find the probability that all the marbles are of different colours?
    
    
    
    
    1/13
    2/17
    3/14
    4/15
    4/18
    Option B
    n(S) = 18C4
    
    n(E) = 4C1 and 3C1 and 5C1 and 6C1
    
    P(E) = n(E) / n(S) = [4C1 or 3C1 or 5C1 or 6C1] / 18C4
    
    P(E) = (4 * 3 * 5 * 6) / [(18 * 17 * 16 * 15) / (1 * 2 * 3 * 4)]
    
    P(E) = 2 / 17