Mixed Quantitative Aptitude Questions Set 134

Directions(1-5): What will be the value in place of question mark "?" in the following questions.

1. 0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?
   0.01731
   0.03027
   0.01235
   0.03027
   0.01626
   Option D
   0.03 × 0.01 – 0.003 ÷ 100 + 0.03 =?
   ? = 0.0003 – 0.00003 + 0.03 = 0.03027
   
   
    



2. 17 × 25 – 240 +? ÷ 41 = 354
   7266
   8890
   6929
   6000
   7254
   Option C
   17 × 25 – 240 +? ÷ 41 = 354
   ? /41 = 354 – 425 + 240
   ⇒ ? = 41 × 169
   ⇒ ? = 6929
   
   
    



3. 3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
   
   100.5
   112.6
   105.5
   124.8
   120.5
   Option D
   3.4 × 2.6 × 5.4 ÷ 1.8 ÷ 0.17 =? ÷ 0.8
   ?/ 0.8 = 156
   ⇒ ? = 124.8
   
   
    



4. 1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
   1.11
   1.46
   2.03
   1.51
   2.21
   Option B
   1701 ÷ 2100 + 3087 ÷ 6300 + 832 ÷ 5200 =?
   ? = 0.81 + 0.49 + 0.16 = 1.46
   
   
    



5. 39% of 450 + 51% of 340 – 40% of 255 =?
   211.5
   246.9
   200.6
   215.5
   220.6
   Option B
   39% of 450 + 51% of 340 – 40% of 255 =?
   ? = 39/100 × 450 + 51/100 × 340 – 40/100 × 255
   = 246.9
   
   
    



6. Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, then find the price of third variety per kg.
   
   178.9
   175.5
   166.5
   150.7
   162.8
   Option B
   Let price of third variety was Rs. A per kg
   Let respective amounts of these tea were x kg, x kg and 2x kg.
   126x + 135x + 2Ax = 153 × 4x
   ⇒ 2A = 351
   ⇒ A = 175.5 rupee per kg
   
   
    



7. One fill pipe A is 3 times faster than second fill pipe B and takes 32 minutes less than the fill pipe B. When will the cistern be full if both pipes are opened together?
   10
   12
   15
   18
   14
   Option B
   
   Let, pipe A takes x minutes to fill the cistern.
   Then, pipe B takes 3x minutes to fill the cistern
   3x – x = 32
   ⇒ x = 16 minutes
   3x = 48 minutes
   So, both pipes can fill the cistern in ( 48×16/48+16) minutes = 12 minutes
   
   
    



8. A vessel contains mixture of milk and water in which water concentration is 30%. If 20% water and 30% milk is taken out and replaced with equal quantity of water, then quantity of water increases by what percent of the initial quantity of water in the mixture.
   
   50%
   90%
   70%
   80%
   60%
   Option C
   Let vessel contains 100 L .
   So required % = 30/100 × 70/30 × 100 = 21/30 × 100 = 70%
   
   
    



9. The marked price of a radio is Rs 480. The shopkeeper allows a discount of 10% and still gains 8%. If no discount is allowed, find his gain percent.
   25%
   15%
   13%
   20%
   10%
   Option D
   M. P. = Rs 480/-
   Discount = 10%
   S.P. = 90/100 × 480 = Rs 432
   P% = 8%
   C.P. = 100/108 × 432 = 400
   If no discount is given then S.P. = M.P. i.e. S.P. = 480
   P% = S. P. −C. P./C. P. × 100
   = 480 – 400/400 × 100 = 80/400 × 100 = 20%
   
   
    



10. The ratio of income of A, B and C is 3 : 7 : 4 and the ratio of their expenditure is 4 : 3 : 5 respectively. If A saves Rs 300 out of Rs 2400, find the savings of C.
    500
    457
    575
    620
    550
    Option C
    Salary of A = 3x = Rs 2400
    Salary of B = 7x = Rs 5600
    Salary of C = 4x = Rs 3200
    Expenditure of A, B and C = 4y, 3y & 5y respectively.
    Saving of A is 300
    Expenditure = 4y = (2400 – 300) = 2100
    𝑦 = 2100/4 = 525
    Expenditure of B = 3y = 1575
    Savings of B = 4025
    Expenditure of C = 5y = 2625
    Savings of C = 575