- x^2-4x+4=0
y^2-9y+18=0x>yx< yX≥Yx≤yX=Y or no relationOption B
1. x^2-4x+4=0
x^2-2x-2x+4=0
x=2,2
2. y^2-9y+18=0
y^2-6y-3y+18=0
y=6,3
- x^2-x-12=0
y^2-y-6=0x>yx< yX≥YX≤YX=Y or no relationOption E
1. x^2-x-12=0
x^2-4x+3x-12=0
x=4,-3
2. y^2-y-6=0
y^2-3y+2y-6=0
y=3,-2
- x^2+7x+10=0
y^2+12y=35=0x>yx< yX≥YX≤YX=Y or no relationOption C
1. x^+7x+10=0
x^2+5x+2x+10=0
x= -5,-2
2. y^2+12y+35=0
y^2+7y+5y+35=0
y= -7,-5
- 25x^2=625
y^2-10y+25=0x>yx< yX≥YX≤YX=Y or no relationOption D
1. 25x^2=625
x=+5,-5
2. y^2-10y+25=0
y^2-5y-5y+25=0
y=5,5
- x^2-x-42=0
2y^2-8y+8=0x>yx< yX≥YX≤YX=Y or no relationOption E
1. x^2-x-42=0
x^2-7x+6x-42=0
x=7,-6
2. 2y^2-8y+8=0
2y^2-4y-4y+8=0
2y=4,4
y=2,2
- x^4=256
y^2-12y+36=0x>yx< yX≥YX≤YX=Y or no relationOption B
1. x^4=256
x=+4,-4
2. y^-12y+36=0
y^2-6y-6y+36=0
y=6,6
- 2x+3y=3
3x+5y=2x>yx< yX≥YX≤YX=Y or no relationOption A
1. 2x+3y=3........(1)
3x+5y=2...........(2)
solving euations (1) and (2) we get,
5(2x+3y=3)=10x+15y=15
3(3x+5y=2)=9x+15y=6
x=9
by putting x=9, in equation(1) we get,
18+3y=3
y=-5
- 3x^2-7x+4=0
4y^2-13y+9=0x>yx< yX≥YX≤YX=Y or no relationOption E
1. 3x^2-4x-3x+4=0
3x=4,4
x=4/3, 4/3
2. 4y^2-13y+9=0
4y^2-9y-4y+9=0
4y=9,4
y=9/4, 1
- x^2=16
y^2+6y+8=0x>yx< yX≥YX≤YX=Y or no relationOption E
1. x^2=16
x=4,-4
2. y^2+6y+8=0
y^2+4y+2y+8=0
y= -4,-2
- 5x^2-8x+3=0
2y^2-16y+32=0x>yx< yX≥YX≤YX=Y or no relationOption B
1. 5x^2-8x+3=0
5x^2-5x-3x+3=0
5x=1, 3/5
2. 2y^2-16y+32=0
2y^2-8y-8y+32=0
2y=8,8
y=4,4
Wednesday, April 7, 2021
Quantitative Aptitude: Quadratic Equations Questions Set 73
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