Mixed Quantitative Aptitude Questions Set 186

1. A metro travelling at 72 km/hr crosses another metro of length equivalent to five-sixth of its own length travelling in opposite direction at 60 km/hr in 9 seconds. Find the length of the second metro?
   110
   120
   130
   140
   150
   Option E
   Let the length of the first metro be x,
   So, the length of second metro = (5/6) * x = 5x/6
   According to the question,
   [x + (5x/6)] / [(72 + 60) * (5/18)] = 9 [11x/6] / [132 * (5/18)] = 9
   x = 180
   Length of second metro = (5x/6) = (5/6) * 180 = 150 m
   
   
    



2. A bag contains 4 red pop sticks, 5 green popsticks and 6 pink pop sticks. If 3 sticks are taken at randomly, then find the probability that 2 sticks are Pink?
   11/12
   27/91
   25/65
   12/97
   13/99
   Option B
   Total probability = 15C3
   Required probability = 6C2 and 9C1
   The probability that 2 are green,
   = > [6C2 and 9C1] / 15C3¬
   = > [15 * 9] / 455
   = > 27/91
   
   
    



3. The perimeter of the room in rectangular shape is 42 meter. The length of the room is twice the breadth of the room. Find the area of the room?
   98
   99
   97
   95
   96
   Option A
   Perimeter of the room= 2 * (l + b) = 42
   l + b = 21
   l = 2b
   According to the question,
   2b + b = 21
   3b = 21
   b = 7 m
   l = 2b = 14 m
   Area of the room = lb = 14 * 7 = 98 Sq m
   
   
    



4. P, Q and R investing Rs. 18000, Rs. 24000 and Rs. 30000 respectively. After 4 months, P withdraws one-third of the amount and Q invested Rs. 16000 more. And after 3 months, R withdraw three-fifth of the amount. Find the total profit at the end of the month, if the share of Q is Rs. 52000?
   Rs. 106733
   Rs. 106350
   Rs. 506750
   Rs. 106000
   Rs. 106750
   Option E
   [18000 * 4 + 18000 * (2/3) * 8] : [24000 * 4 + 40000 * 8] : [30000 * 7 + 30000 * (2/5) * 5]
   = > [72000 + 96000] : [96000 + 320000] : [210000 + 60000]
   = > 168000 : 416000 : 270000
   = > 84 : 208 : 135
   Q’s share = 208’s = 52000
   1’s = 250
   Total profit = 427’s = Rs. 106750
   
   
    



5. Man can do a work in 15 days, Woman can do it in 12 days but Boy can do (3/4)th of the work in 18 days. Find the time taken by all together to complete the work?
   1 1/23
   4 4/23
   5 5/23
   6 4/23
   1 4/21
   Option
   man’s one day work = 1/15
   Woman’s one day work = 1/12
   Boy can do the whole work in, = 18 * (4/3) = 24 days
   Boy’s one day work = 1/24
   (Three)’s one day work = (1/15) + (1/12) + (1/24)
   = > (8 + 10 + 5)/120
   = > 23/120
   They can complete the whole work in, = 120/23 = 5 5/23 days
   
   
    



6. Person 1 is thrice as good a workman as person 2 and so takes 30 days less than person 2 for doing a job. Calculate the time in which they can do the job together is.
   12
   12.5
   11
   11.25
   13
   Option D
   Let person 1 can finish the whole work in x days.
   Person 2 can finish the same work in 3x days.
   then 3x-x= 2x= 30
    x= 15 days
   Person 1 can finish the work in 15 days.
   Person 2 can finish in 45 days.
   A+B work = 1/15 + 1/45 = 4/45
   A+B can finish the work in 45/4 = 11 ¼ days
   
   
    



7. 32 men and 24 women together can complete a work in 16 days. 40 men can complete the same work in 32 days.How many days will 32 women can complete the same work ?
   10
   20
   30
   40
   50
   Option B
   (32 M + 24 W)* 16= 40 M * 32
   = 40M * 16 * 2
   32M + 24W = 80M
   24W =48M
   1W=2M-------1
   32W=64M-----2
   Now 40 men complete the work in 32 days.
   So 64 men complete the same work in 32* 40 / 64 = 20 days.
   Hence 32 women complete the same work in 20 days.
   
   
    



8. Four examiners can examine a certain number of answer papers in 10 days by working for 5 a day. for how many hours in a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?
   10
   15
   20
   25
   30
   Option A
   M1 * D1* H1 / W1 = M2 * D2* H2 / W2
   M1 = 4 D1= 10 H1= 5
   W1 = 1 M2 =2 D2 = 20
   H2 = ? W2= 2
   4*10 *5/1 = 2* 20 *H2/2
   =>H2= 10H
   
   
    



9. 2 boys and 3 girls together or 4 boys can complete a piece of work in 20 days. 3 boys and 3 girls will complete the same work in how many days?
   15
   16
   17
   18
   19
   Option B
   2 boys + 3 girls= 4 boys
   =>2 boys = 3 girls
   =>3 boys + 3 girls = 5 boys ( 3 girls= 2 boys)
   M1D1= M2D2
   =>4* 20 = 5 *D2
   D2 = 16 days.
   
   
    



10. Varun gets Rs. 700 for every day that the works. If he runs Rs.19600 in a month of 62 days, for how many days did he work?
    23
    25
    27
    28
    40
    Option D
    Varun gets Rs.700 for 1 day of work
    Amount received by varun for 62 days.
    Number of days Varun worked in a month = 19600/ 700 =28 days.