Quantitative Aptitude: Data Interpretation Questions Set 141

Directions (1-5): The given bar graph shows the rate of interest per year by 4 various chit companies for deposits under three different plan (A, B and C).

1. Raj invested an amount in plan A of finance S for two years and he also invests the same amount in plan C of finance T for two years. If the total amount of simple interest accrued from the two plans is Rs.880, then what is the principal amount?
   1000
   1500
   2000
   2500
   3000
   Option C
   x * 12 * 2/100 + x * 10 * 2/100 = 880
   24x + 20x = 88000
   x = Rs. 2000
   
   
    



2. The finance U offers compound interest under plan B and finance V offer simple interest under plan B. What is the difference between the interests earned under these plans in two years, if the principal amount is Rs.8400?
   543
   445
   924
   876
   456
   Option C
   SI = 5 * 8400 * 2/100
   SI = Rs. 840
   CI = 8400 * (1 + 10/100)2 – 8400
   CI = Rs. 1764
   Required Difference = 1764 – 840 = Rs. 924
   
   
    



3. Sam invested his amount Rs.4500 for eight years with finance T under plan B which is offering simple interest and Prem invested Rs.6000 for three years with finance V under plan C which is offering compound interest. What is the difference between the interest earned by Sam and Prem?
   2112
   2008
   2432
   2002
   2080
   Option A
   Interest amount earned by Sam = 4500 * 18 * 8/100 = Rs. 6480
   Interest amount earned by Prem = 6000 * (1 + 20/100)3 – 6000
   = Rs. 4368
   Required Difference = 6480 – 4368 = Rs. 2112
   
   
    



4. Krupa invested Rs.3000 in finance S under plan C which is offering simple interest for 5 years and Rs.2000 in finance V under plan A which is also offering simple interest for 4 years, What is the total interest earned by Krupa?
   3000
   3210
   3120
   3222
   3111
   Option B
   Total interest = 3000 * 15 * 5/100 + 2000 * 12 * 4/100
   = 2250 + 960
   = Rs. 3210
   
   
    



5. The finance T offers compound interest under plan C and finance U offer simple interest under plan B. What is the difference between the interests earned under these plans in three years, if the principal amount is Rs.4800?
   123
   134.4
   148.8
   112.7
   126.9
   Option C
   Difference = P * r * r/100 * 100 * 100 * (300 + r)
   = 4800 * 10 * 10/100 * 100 * 100 * (300 + 10)
   = 48 * 310/100
   = Rs. 148.8
   
   
    


Directions (6-10): The bar graph shows the no. of Red, Blue and Pink color cars in a garage A, B, C, D and E Line graph shows the probability of a green color car taken from each garage.
6. 
   If 25% of red car taken from garage A and added to garage E, then find the probability of taken two car both are pink colour in garage E
   105/1378
   10/1378
   105/137
   105/378
   16/1378
   Option A
   Garage A:
   Let us take the no. of green colour car be x
   Probability = xc1/(32+x)c1
   9/25 = x/(32+x)
   32*9 +9x = 25x
   16x = 32*9=> x= 18 green colour car
   Garage B:
   Let us take the no. of green colour car be x
   Probability = xc1/(34+x)c1
   3/20 = x/(34+x)
   3*34+ 3x = 20x
   =>3*34= 17x
   X= 6 green colour car
   Garage C:
   Let us take the no. of green colour car be x
   Probability = xc1/(40+x)c1
   1/5 = x/(40+x)
   =>40+x= 5x
   =>4x=40 =>x= 10 green colour car
   Garage D:
   Let us take the no. of green colour car be x
   Probability = xc1/(26+x)c1
   2/15 = x/(26+x)
   52+2x= 15x
   =>13x= 52
   => x= 4 green colour car
   Garage E:
   Let us take the no. of green colour car be x
   Probability = xc1/(40+x)c1
   1/5 = x/(40+x)
   =>40+x= 5x
   =>4x=40 =>x= 10 green colour car
   
   1) Answer: c)
   Total number of balls in garage E = [(12*25/100)+15] +10+15+10
   = 18+10+15+10
   = 53
   Required probability = 15c2/53c2 = (15*14)/(53*52)
   = 105/1378
   
   
    



7. If the total no of red colour car and pink colour car from all the garages (A, B, C, D and E) are taken out and filled in a new garage P, then 2 car taken out from garage P find the probability of different colours
   3869/78
   386/7875
   3869/7875
   369/7875
   318/7875
   Option C
   Total number of red colour cars in garage P = (12+8+10+8+15) = 53
   Total number of pink colour cars in garage P = (12+16+18+12+15) = 73
   Required probability = (53*73)/(53+73)c2
   = 53*73/(126*125/1*2) = 3869/7875
   
   
    



8. Four car taken from garage C, then find the probability of different colour
   216/2303
   216/230
   516/2303
   216/303
   200/2303
   Option A
   Required probability = (10*12*18*10)/50c4
   = (10*12*18*10)/(50*49*48*47/1*2*3*4)
   = (24*9)/(49*47)
   = 216/2303
   
   
    



9. Total number of balls in garage B and D together is approximately what percentage of the total number of balls in garage C and E together?
   40%
   70%
   60%
   75%
   80%
   Option B
   Required percentage
   = [(8+10+16+6+8+6+12+4)/(10+12+18+10+15+10+15+10)]*100
   = 70/100 * 100 = 70%
   
   
    



10. Two cars took randomly from garage B. What is the probability of at least one pink colour car?
    42/65
    42/63
    42/61
    42/67
    39/65
    Option A
    Required probability = 1- 24c2/40c2
    = 1 – (24*23/40*39)
    = 1- 23/65
    = 42/65