Monday, October 7, 2019

Quant Test for IBPS PO Prelims Exam set – 22

  1. Lakshya got 5000 as his share out of the total profit of 9000. Yogesh had invested 3000 rupees for 6 months while Lakshya invested for the whole year. Find the amount invested by Lakshya.
    1758
    1800
    1875
    1990
    1772
    Option C
    Amount invested by Lakshya = x
    12x : 3000*6
    x:1500
    Lakshya share = [x/(1500+x)]*9000 = 5000
    x = 75*25 = 1875

     


  2. The average age of a Shravan and his wife was 25 years when they were married 7 years ago. Now the average age of Shravan, wife and his son is 23 years. Find the age of son now.
    4
    3
    5
    2
    6
    Option C
    (s+w – 14)/2 = 25
    s+w = 64
    Now, (s+w+son)/3 = 23
    S = 69-64 = 5 years

     


  3. Hina can do a piece of work in 16 days. Gita can do the same work in 64/5 days, while Sita can do it in 32 days. All of them started to work together but Hina leaves after 4 days. Gita leaves the job 3 days before the completion of the work. How long would the work last?
    12
    9
    7
    8
    10
    Option B
    Let the work lasted for x days,
    Hina’s 4 day’s work + Gita (x – 3) day’s work + Sita’s x day’s work = 1
    ⇒ (4/16) + (x – 3) / (64/5) + x/32 = 1
    ⇒ 5(x – 3)/64 + x/32 = 1 – 1/4
    ⇒ [5(x – 3) + 2x] / 64 = 3/4
    ⇒ 7x – 15 = 48
    x = (48 + 15)/7 = 63/7 = 9 days

     


  4. Arun takes thrice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat in still water and stream is:
    2:3
    4:5
    2:1
    5:6
    3:4
    Option C
    Speed downstream = x kmph
    Speed upstream = 3x kmph
    (3x+x)/2 : (3x-x)/2
    4x/2 : 2x/2 = 2:1

     


  5. A and B are two persons sitting in a circular arrangement with 8 other persons. Find the probability that both A and B sit together.
    3/7
    2/9
    5/8
    1/4
    3/8
    Option B
    Total outcomes = (10 -1)! = 9!
    Favourable outcomes = (9 -1)!*2!
    Probability = 2/9

     
  6. Directions(6-10): Find the values of x and y, compare and choose a correct option.

  7. I.x^2 – 26x + 168 = 0
    II.y^2 – 30y + 209 = 0
    x >= y
    x > y
    y >= x
    No relation
    y > x
    Option D
    I.x^2 – 26x + 168 = 0
    =>x^2 – 12x – 14x + 168 = 0
    =>(x-12)(x-14) = 0
    =>x = 12,14
    II.y^2 – 30y + 209 = 0
    =>y^2 – 19y – 11y + 209 = 0
    =>(y-11)(y-19) = 0
    =>y = 11,19
    No relation

     


  8. I.x^2 – 3x – 40 = 0
    II.y^2 – 17y + 72 = 0
    x > y
    x >= y
    y >= x
    y > x
    No relation
    Option C
    I.x^2 – 3x – 40 = 0
    =>x^2 – 8x + 5x – 40 = 0
    =>(x-8)(x+5) = 0
    =>x = 8,-5
    II.y^2 – 17y + 72 = 0
    =>y^2 – 9y – 8y + 72 = 0
    =>(y – 9)(y – 8) = 0
    =>y = 9,8
    y >= x



     


  9. I.x^2 + 17x + 72 = 0
    II.y^2 + 19y + 90 = 0

    x > y
    x >= y
    No relation
    y >= x
    y > x
    Option B
    I.x^2 + 17x + 72 = 0
    =>x^2 + 9x + 8x + 72 =0
    =>(x + 8)(x+9) = 0
    =>x = -8,-9
    II.y^2 + 19y + 90 = 0
    =>y^2 + 10y + 9y + 90 = 0
    =>(y+ 9)(y+10) = 0
    =>y = -9,-10
    x >= y

     


  10. I.x^2 – 19x + 88 = 0
    II.y^2 – 27y + 182 = 0
    x > y
    No relation
    x >= y
    y > x
    y >= x
    Option D
    I.x^2 – 19x + 88 = 0
    =>x^2 – 11x – 8x + 88 = 0
    =>(x – 11)(x – 8 ) = 0
    =>x = 11,8
    II.y^2 – 27y + 182 = 0
    =>y^2 – 13y – 14y + 182 = 0
    =>(y – 13)(y – 14) = 0
    =>y = 13,14
    y > x

     


  11. I.x^2 – 8x – 128 = 0
    II.y^2 + y – 90 = 0
    No relation
    x > y
    x >= y
    y >= x
    y > x
    Option A
    I.x^2 – 8x – 128 = 0
    =>x^2 – 16x + 8x – 128 = 0
    =>(x – 16)(x+8) = 0
    =>x = 16,-8
    II.y^2 + y – 90 = 0
    =>y^2 + 10y – 9y – 90 = 0
    =>(y + 10)(y – 9) = 0
    =>y = -10,9
    No relation

     




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