Quant Test for IBPS PO Prelims Exam set – 28

Directions(1-5): What approximate value will come in place of question mark '?' in the following questions.

1. 16.12*15.94 + 654.92 – 344.83 = ?*5.95
   88
   84
   90
   80
   95
   Option C
   16.12*15.94 + 654.92 – 344.83 = ?*5.95
   =>16*16 + 655 – 345 = ?*6
   =>256 +655 – 345 = ?*6
   =>911 – 345 = ?*6
   =>566/6 =?
   =>? = 90
   
   
    



2. 35.1% of 1599 = ? – (449.96/6.12)*2
   620
   655
   750
   815
   710
   Option E
   35.1% of 1599 = ? – (449.96/6.12)*2
   =>35% of 1600 = ? – (450/6)*2
   =>560 = ? – 75*2
   =>560 = ? – 150
   =>? = 710
   
   
    



3. 30.11*(1025)^1/2 + 196 = ?^2 – 287
   40
   38
   25
   30
   48
   Option B
   30.11*(1025)^1/2 + 196 = ?^2 – 287
   =>30*(1024)^1/2 + 196 = ?^2 – 287
   =>30*32 + 196 = ?^2 – 287
   =>960 + 196 + 287 = ?^2
   =>?^2 = 1444
   =>? = 38
   
   
    



4. 18.003*3.99 *(135.003 / 26.97) – ( 15.001*3.94) = ?
   289
   250
   300
   350
   324
   Option C
   18.003*3.99 *(135.003 / 26.97) – ( 15.001*3.94) = ?
   =>18*4*(135/27)- (15*4) = ?
   =>72*5 – 60 = ?
   =>? = 360 – 60
   =>? = 300
   
   
    



5. 41.97 *5.12/2.99 + 49.89 = ?*1.99
   55
   45
   40
   52
   60
   Option E
   41.97 *5.12/2.99 + 49.89 = ?*1.99
   =>42*5 /3 + 50 = ?*2
   =>70 + 50 = ?*2
   =>? = 60
   
   
    



6. A pipe can fill a cistern in 8 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the cistern completely?
   6
   4
   5
   8
   9
   Option C
   Part filled by P and Q = In One hour pipe can fill = 1/8
   Time is taken to fill half of the tank = 1/2 * 8 = 4 hours
   Part filled by four pipes in one hour = (4*1/8) = 1/2
   Required Remaining Part = 1/2
   Total time = 4 + 1 = 5 hours
   
   
    



7. Dhipan borrowed Rs.800 at 6% per annum and Shahrukh borrowed Rs.600 @ 10% per annum. After how much time, will they both have equal debts?
   50/3
   42/3
   51/2
   47/3
   53/3
   Option A
   800+(800*6*T)/100 = 600+(600*10*T)/100
   T=50/3 yr.
   
   
    



8. The perimeter of a rectangular ppalyground is 210 m. Find the cost of gardening 2 m broad boundary around rectangular playground whose perimeter The cost of gardening is Rs 14 per m2.
   5210
   6200
   6104
   6000
   5480
   Option C
   Given 2(l+b) = 210
   2 m broad boundary means increase in l and b by 4 m
   So area of the boundary will be [(l+4)(b+4) – lb] = 4(l+b) + 16 = 2*[2(l+b)] + 16 = 2*210 + 16 = 436 m2
   So cost of gardening = 436*14 = Rs. 6104
   
   
    



9. One type of liquid contains 20 percent of milk and second type of liquid contains 40 percent milk. If 4 part of the first and 6 part of the second are mix, then what is the percent of water in the mixture.
   74%
   70%
   68%
   60%
   50%
   Option C
   Let water = 80ltr and 60ltr in first and second mixture respectively
   Percent of water = [(80*4 + 60*6)/1000]100 = 68%
   
   
    



10. A urn contains 4 red balls, 5 green balls and 6 white balls, if one ball is drawn at random, find the probability that it is neither red nor white.
    1/5
    1/7
    1/6
    1/3
    1/4
    Option D
    Probability = 5c1/15c1 = 1/3