- A and B undertake to complete a piece of work for Rupees 1200. A can do it in 8 days, B can do it in 12 days and with the help of C they complete the work in 4 days. Find the share of C?
180220200145175Option C
1/8 + 1/12 + 1/C = 1/4, we get C = 24 days
now efficiency of A, B and C are in the ratio of 1/8 :1/12 : 1/24
3:2:1, so share of C is 1/6 * 1200 = 200
- One year before, Manju was six times as old as her daughter. Six years hence, Manju’s age will exceed her daughter’s age by 20 years. The ratio of the present ages of Manju and her daughter is?
4:35:11:24:56:7Option B
Ages of Manju and her daughter = 6x, x
[6x + 1 + 6] – [x + 1 + 6] = 20
5x = 20; x = 4
Ratio = 6x + 1 : x + 1 = 25 : 5 = 5:1
- A sum of rupees 3903 is divided between P and Q such that the share of P at the end of 8 years is equal to the share of Q after 10 years. Find the share of P if rate of interest is 4% compounded annually.
21212000199820282100Option D
P*(1 + 4/100)^8 = (3903 – P)*(1 + 4/100)^10
= 2028
- Speed of a man in still water is 4 km/hr and the river is running at 2 km/hr. The total time taken to go to a place and come back is 4 hours. What is the distance travelled?
85694Option C
Distance = time * [B^2 – R^2] / 2*B
Distance = 4* [4^2 –2^2] / 2*4
= 6 km
- A bag contains 3 red balls and 8 blacks ball and another bag contains 5 red balls and 7 blacks balls, one ball is drawn at random from either of the bag, find the probability that the ball is red.
88/26371/29066/25191/26461/263Option D
Probability = probability of selecting the bag and probability of selecting red ball
(1/2)*(3/11) + (1/2)*(5/12) = 91/264
Directions(6-10): Find the wrong term of the following number series.
- 4, 6, 18, 49, 201, 1011
4964181011Option D
4 × 1 + 2 = 4 + 2 = 6
6 × 2 + 3 = 12 + 3 = 15 == 18
15 × 3 + 4 = 45 + 4 = 49
49 × 4 + 5 = 196 + 5 = 201
201 × 5 + 6 = 1005 + 6 = 1011
- 48, 72, 108, 162, 243, 366
2437236610848Option C
48 ×3/2 = 72
72 ×3/2 = 108
108 × 3/2= 162
162 × 3/2 = 243
243 ×3/2 = 364.5 == 366
- 2, 54, 300, 1220, 3674, 7350
54367421220300Option B
2 × 6 + 7 × 6 = 12 + 42 = 54
54 × 5 + 6 × 5 = 270 + 30 = 300
300 × 4 + 5 × 4 = 1200 + 20 = 1220
1220 × 3 + 4 × 3 = 3660 + 12
= 3672 == 3674
3672 × 2 + 3 × 2 = 7344 + 6 = 7350
- 8, 27, 64, 125, 218, 343
272188125343Option B
2^3 = 8 : 3^3 = 27
4^3 = 64 : 5^3 = 125
6^3 = 216 == 218
7^3 = 343
- 19, 68, 102, 129, 145, 154
9590102110120Option C
19 + 7^2 = 19 + 49 = 68
68 + 6^2 = 68 + 36 = 104 == 102
104 + 5^2 = 104 + 25 = 129
129 + 4^2 = 129 + 16 = 145
145 + 3^2 = 145 + 9 = 154
Friday, October 11, 2019
Quant Test for IBPS PO Prelims Exam set – 25
Labels:
Sectional Tests
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment