- In how many ways can 3 roses and 4 tulips 2 jasmines can be arranged in a garland such that all roses tied together and all tulips are tied together and jasmines also tied together?876864867912834Option B
Required number of ways = 3( 3! * 4! *2!)
=3* 3 * 2 * 4* 3 * 2 *2
=>864 ways.
- In how many ways the word “ note book “ can be arranged?56702456672056706120Option C
notebook.
There are 8 letters. o is repeated three times
So number of words formed=8!/ 3!
=6720 ways
- There are two positive integers x and y .What is the probability that x+y is even?1/21/31/41/51/6Option A
Sum of positive integers is either odd or even.
Hence the required probability= ½
- The sum of three consecutive odd number is 93.Then what will be the middle number if they arranged in descending order?3031293335Option B
Let the three numbers be 2a +1 , 2a+3, 2a +5
Given 2a+1 + 2a+3 +2a+ 5= 93
=>6a +6 = 93
=> 6a= 84
=>a=14
Hence the numbers are = 29,31,33
So the middle number is 31.
- A bag contains 6 nestle bars and 4 kitkat bars. Two bars given at random to the children.
Then what is the probability that they are of same bars?2/153/155/156/257/15Option E
Required probability = 6C2 + 4C2 / 10C2
= 30+ 12/ 90 = 42/90
=7/15
- In how many different words can be formed from word ENCYCLOPEDIA such that all vowels come together?2015020140201602098020790Option C
NCYCLPD(all vowels)
So number of letters= 8 also c is repeated twice.
Required probability = 8!/ 2! = 20160 ways
- Out of all the 2-digit integers between 1 and 50, a 2-digit number has to be selected at random.
What is the probability that the selected number is not divisible by 13?31/4032/4025/4033/4037/40Option E
There are total 40 two digit numbers, out of them 3 are divisible by 13, these are 13, 26, 39
Therefore, probability that selected number is not divisible by 13 = 1 – 3/40 = 37/40
- How many different words can be arranged with letters of the word STENCIL when vowels occupied even places?620720360440580Option B
Vowels are 2, places are 3. So they are arranged in 6 ( 3C2 * 2! ) ways.
Consonants can be arranged in 5! = 120 ways.
Total arrangement = 720 ways( 120*6).
- There are 2 red balls, 5 orange and 4 purple balls .Two balls are drawn at random.What is the probability that one is red the other is orange or purple?12/5511/5516/5518/5517/55Option D
There are 2 red balls and 9 other color balls. So total balls= 11
2 balls drawn at random,
=> required probablity= 2C1 * 9C1/11C2
=2*9/11*10/2
=>36/110 =18/55
- There are 8 students are selected from dance school for dance competition.The total number of students are 18.
In how many ways can be the selection be made so that 2 students are always included?80085005600670079009Option A
If 2 members are always included
The total number of ways= 2C2 * 16 C 2
=8008
Friday, November 8, 2019
Quantitative Aptitude: Probability Questions – Set 11
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