Quantitative Aptitude: Data Interpretation Questions Set 130

Directions(1-5):Answer the questions based on the following information. The graph given below shows the total number of units produced by five companies P,Q,R,S and T and percentage of units sold by respective company in 2010.

1. What is the difference between the number of units which remain unsold by company S and T?
   5000
   5200
   4600
   4000
   4800
   Option C
   Required Difference = 6600 -2000 = 4600
   
    



2. Number of units sold by company R is how much percent more or less than the number of units sold by company S?
   14.2%
   17.5%
   19.7%
   22.2%
   10.9%
   Option B
   Percentage = [(6000 - 4950)/6000 ]*100 = 17.5%
   
    



3. What is the average number of unsold units of companies P,R and T together?
   4200
   3215
   3500
   4750
   3550
   Option D
   Average = (3600+4050+6600)/3 = 4750
   
    



4. Company R has three types of unsold products (P,Q,R), out of which 60% were of the type P while type Q and R were in the ratio 5:4 resp. Find the number of type Q products of company R which remain unsold.
   985
   900
   850
   800
   788
   Option B
   Total number of products of type Q and type R were unsold = 0.40*4050 = 1620
   Number of type Q which remain unsold = 5/9*1620 = 900
   
   
    



5. What is the total number of units sold by company P and Q together in 2010?
   7500
   5400
   7000
   6400
   6200
   Option D
   Total number of units = 2400+4000 = 6400
   
    
Directions(6-10): Answer the questions based on the given information. The graph given below shows the number of students who play Cricket and Badminton from five different schools. One student play one game.


6. Find the average number of students who play Badminton in school A,B and D.
   200
   180
   190
   240
   210
   Option D
   Required Average = (260+180+280)/3 = 240
   
    



7. What is the difference between the average number of students who play Cricket in school A and B together and the average number of students who play Badminton in school C and D?
   20
   25
   32
   30
   45
   Option D
   Difference = (240+280)/2 – (210+250)/2 = 30
   
    



8. If the ratio of the number of boys to girls who play Cricket in school D is 2:3, Find the number of boys who play Cricket in school D?
   80
   100
   90
   85
   96
   Option E
   Number = (240/5)*2 = 96
   
    



9. Find the ratio of the number of students who play Cricket in school C to the number of students who play Badminton in B.
   4:5
   5:6
   7:5
   2:3
   8:9
   Option E
   Ratio = 160:180 = 8:9
   
    



10. The number of students who play Cricket in E is how much percent less than the number of students who play Badminton in A and C together?
    20%
    30%
    40%
    50%
    60%
    Option C
    Difference = (260+240)- 300 = 200
    Percentage = 200/500*100 = 40%