Quantitative Aptitude: Data Interpretation Questions Set 144

Directions (1-5): Study the following information carefully and answer the questions that follow: Monthly salary of three workers P, Q and R in the ratio of 4: 6: 5. S’s monthly salary is 33.33% more than the R’s monthly salary.T’s spends is half of the S’s monthly salary which is five times the monthly savings of T. P and Q saves same amount in monthly which is 50% of the amount saved by S in monthly. S saves 3/2nd of the amount saves by T in monthly. T’s monthly salary is equal to the S’s monthly spends.R’s monthly spends is two times of the amount saves by him. Q invests his monthly savings in two different plans A and B in the ratio of 2: 1. Plan A offers 10% simple interest for two years and plan B offers 20% compound interest for two years compounded annually. Total interest obtained by Q in both the plans together is Rs. 1680.

1. What is the ratio of R’s monthly spends to that of Q’s monthly spends?
   
   
   2: 1
   2: 5
   2: 9
   2: 3
   2: 7
   Option D
   Let us take Q saves Rs. 3x amount
   by question,
   (2x * 10 * 2)/100 + (x * 44)/100 = 1680
   40x/100 + 44x/100 = 1680
   84x/100 = 1680
   = > x = 1680 * (84/100) = Rs.2000
   Q saves monthly Rs.6000
   P’s monthly savings = Q’s monthly savings = 50% of S’s monthly savings
   P‘s monthly savings = Rs.6000
   Q’s monthly savings = Rs.6000
   S’s monthly savings = 6000 * (100/50) = Rs.12000
   T’s monthly savings = 2/3rd of S’s monthly savings = 12000 * 2/3 = Rs.8000
   S’s monthly salary = 5 * T’s monthly savings = 5 * 8000 = Rs.40000
   T’s monthly spends = ½ * S’s monthly salary = 40000 * ½ = Rs.20000
   S’s monthly spends = 40000 – 12000 = Rs.28000
   T’s monthly salary = S’s monthly spends = Rs.28000
   S’s monthly salary = (100 + 33.33)% of R’s monthly salary
   40000 = (100 + 100/3)% of R’s monthly salary
   40000 = 400/300 * R’s monthly salary
   40000 * (3/4) = R’s monthly salary
   R’s monthly salary = Rs.30000
   Ratio of R’s spends to savings = 2: 1
   R’s monthly spends = 30000 * (2/3) = Rs.20000
   R’s monthly savings = 30000 * (1/3) = Rs.10000
   P’s monthly salary = 30000 * (4/5) = Rs.24000
   Q’s monthly salary = 30000 * (6/5) = Rs.36000
   Q’s monthly spends = 36000 – 6000 = Rs.30000
   Q’s monthly salary = 200% of P’s monthly spends
   36000 = 2 * P’s monthly spends
   P’s monthly spends = 36000/2 = Rs.18000
   Required ratio = 20000: 30000 = 2: 3
   
   
    



2. P and R invested their monthly savings in a business. After 6 months, S also joined with his monthly savings in the business. Find the share of P if the total profit at the end of the year is Rs.18700?
   Rs.5390
   Rs.6700
   Rs.5800
   Rs.3400
   Rs.5100
   Option E
   Profit ratio of P, Q and R = (6000 * 12): (10000 * 12): (12000 * 6)
   = 72: 120: 72
   = 3: 5: 3
   P’s share = 18700 * (3/11) = Rs.5100
   
   
    



3. P and Q’s monthly salary is what percentage of the T’s monthly spends?
   100%
   300%
   200%
   350%
   50%
   Option B
   Required percentage = (24000 + 36000)/20000 * 100
   = 60000/20000 * 100
   = 300%
   
   
    



4. What is the difference between the R, S and T’s monthly salary together and P, Q and S’s monthly spends?
   Rs.32000
   Rs.20000
   Rs.42000
   Rs.12000
   Rs.22000
   Option E
   Required difference = (30000 + 40000 + 28000) – (18000 + 30000 + 28000)
   = Rs.22000
   
   
    



5. Who among the following person has maximum savings percentage?
   p
   Q
   R
   S
   T
   Option C
   P’s savings percentage = 6000/24000 * 100 = 25%
   Q’s savings percentage = 6000/36000 * 100 = 16.67%
   ’s savings percentage = 10000/30000 * 100 = 33.33%
   S’s savings percentage = 12000/40000 * 100 = 30%
   T’s savings percentage = 8000/28000 * 100 = 28.57%
   R has maximum savings percentage.
   
   
    


Directions (6-10): Study the following bar graph and answer the questions that follows:
6. Find the difference between the average number of weights loss by P to that of Q on all the given days together.
   15
   16
   17
   18
   19
   Option D
   The average number of weights loss by P on all the given days together
   = > (120 + 80 + 180 + 150 + 220) / 5 = 150
   The average number of weights loss by Q on all the given days together
   = > (170 + 120 + 90 + 200 + 260) / 5 = 168
   Required difference = 168 – 150 = 18
   
   
    



7. Find the difference between total weights loss by P on Monday and Friday together to that of total weights loss by Q on Tuesday and Thursday together.
   20
   30
   24
   17
   19
   Option A
   The total weights loss by P on Monday and Friday together
   = >120 + 220 = 340
   The total weights loss by Q on Tuesday and Thursday together
   = >120 + 200 = 320
   Required difference = 340 – 320 = 20
   
   
    



8. If the average number of weights loss by P and Q from Monday to Saturday is 160 and 168 respectively, then find the total number of weights loss by P and Q on Saturday.
   234
   378
   267
   438
   213
   Option B
   The number of weights loss by P on Saturday
   = > (160 * 6) – (120 + 80 + 180 + 150 + 220)
   = >960 – 750 = 210
   The number of weights loss by Q on Saturday
   = > (168 * 6) – (170 + 120 + 90 + 200 + 260)
   = > 1008 – 840 = 168
   The total number of weights loss by P and Q on Saturday
   = >210 + 168 = 378
   
   
    



9. Total weights loss by both of them together on Tuesday is approximately what percentage of total weights loss by both of them together on Thursday?
   37
   47
   57
   67
   68
   Option C
   Total weights loss by both of them together on Tuesday
   = > 80 + 120 = 200
   Total weights loss by both of them together on Thursday
   = > 150 + 200 = 350
   Required % = (200 / 350) * 100 = 57.14 % = 57 %
   
   
    



10. The average marks of English of a class of 40 students is 36. If the marks of three students were told wrong as 48, 52 and 56 of the actual marks 58, 66 and 72 respectively, then what would be the correct average?
    33
    34
    35
    36
    37
    Option E
    The average marks of English of a class of 40 students = 36
    Total marks = 40 * 36 = 1440
    Correct average = [1440 – (48 + 52 + 56) + (58 + 66 + 72)] / 40
    = > [1440 – 156 + 196] / 40
    = > 1480 / 40 = 37